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arkietech
Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
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 Posted: Fri Aug 25, 2017 5:25 am Post subject: VH082517 |
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| Code: | *-----------*
|...|...|4.3|
|.43|..1|5..|
|7.5|.4.|...|
|---+---+---|
|.1.|39.|7..|
|6..|4.7|..8|
|..8|.62|.4.|
|---+---+---|
|...|.7.|8.4|
|..7|1..|93.|
|4.6|...|...|
*-----------*
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Ajò Dimonios
Joined: 01 May 2017
Posts: 339
Location: Sassari Italy
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| Posted: Fri Aug 25, 2017 8:24 am Post subject: |
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Hi everyone
| Code: |
+----------------+------------+--------------+
| 1289 6 129 | 7 258 59 | 4 289 3 |
| 289 4 3 | 6 28 1 | 5 2789 279 |
| 7 289 5 | 289 4 3 | 6 1289 129 |
+----------------+------------+--------------+
| 25 1 4 | 3 9 8 | 7 6 25 |
| 6 2359 29 | 4 1 7 | 23 259 8 |
| 39 7 8 | 5 6 2 | 13 4 19 |
+----------------+------------+--------------+
| 12359 2359 129 | 29 7 6 | 8 25 4 |
| 258 258 7 | 1 258 4 | 9 3 6 |
| 4 2589 6 | 289 3 59 | 12 1257 1257 |
+----------------+------------+--------------+
|
Play this puzzle online at the Daily Sudoku site
Solution with one step after basics.
AIC (2=5)R4C1-(5)R5C2=(5)R5C8-(5=2)R7C8-(2)R123C8=(2)R23C9-(2)R4C9=>-2R4C9=>solution stte.
Ciao a Tutti
Paolo |
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ZeroAssoluto
Joined: 05 Feb 2017
Posts: 942
Location: Rimini, Italy
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| Posted: Fri Aug 25, 2017 8:36 am Post subject: |
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Hi everyone,
| Code: |
+----------------+------------+--------------+
| 1289 6 129 | 7 258 59 | 4 289 3 |
| 289 4 3 | 6 28 1 | 5 2789 279 |
| 7 289 5 | 289 4 3 | 6 1289 129 |
+----------------+------------+--------------+
| 25 1 4 | 3 9 8 | 7 6 25 |
| 6 2359 29 | 4 1 7 | 23 259 8 |
| 39 7 8 | 5 6 2 | 13 4 19 |
+----------------+------------+--------------+
| 12359 2359 129 | 29 7 6 | 8 25 4 |
| 258 258 7 | 1 258 4 | 9 3 6 |
| 4 2589 6 | 289 3 59 | 12 1257 1257 |
+----------------+------------+--------------+
|
Play this puzzle online at the Daily Sudoku site
some solutions
XY-Wing 2,3,9 in r6c1, r5c37 and -3 in r5c2, r6c7
or
XY-Wing 2,5,9 in r7c48, r9c6 and -5 in r9c89
or
XYZ-Wing 2,5,9 in r4c9, r5c38 and -2 in r5c7
Ciao Gianni |
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Ajò Dimonios
Joined: 01 May 2017
Posts: 339
Location: Sassari Italy
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| Posted: Fri Aug 25, 2017 11:19 am Post subject: |
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Hi everyone
Other solutions with one step.
[(9)R5C8-(9=2)R5C3 and (9-5)R5C8=(5-2)R4C9=(2)R4C1=>contradiction two singles 2 in box 4=>-9R5C8=>stte.
[(2)R7C8-(2=9)R7C4 and (2-5)R7C8=(5)R9C89-(5=9)R9C6]=>contradiction two singles 9 in box 8=>-2R7C8=>stte.
Ciao a Tutti
Paolo |
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Clement
Joined: 24 Apr 2006
Posts: 1111
Location: Dar es Salaam Tanzania
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| Posted: Fri Aug 25, 2017 12:51 pm Post subject: VH082517 |
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| Code: |
+------------------------+--------------------+----------------------+
| 1289 6 129 | 7 258 59 | 4 289 3 |
| 289 4 3 | 6 28 1 | 5 2789 279 |
| 7 289 5 | 289 4 3 | 6 1289 129 |
+------------------------+--------------------+----------------------+
| 25 1 4 | 3 9 8 | 7 6 25 |
| 6 2359 c29 | 4 1 7 |b23 d259 8 |
| 39 7 8 | 5 6 2 |a13 4 e9-1 |
+------------------------+--------------------+----------------------+
| 12359 2359 129 | 29 7 6 | 8 25 4 |
| 258 258 7 | 1 258 4 | 9 3 6 |
| 4 2589 6 | 289 3 59 | 12 1257 1257 |
+------------------------+--------------------+----------------------+
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(1=3)r6c7 - (3=2)r5c7 - (2=9)r5c3 - r5c8 = (9)r6c9 => - 1 r6c9; stte |
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Ajò Dimonios
Joined: 01 May 2017
Posts: 339
Location: Sassari Italy
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| Posted: Fri Aug 25, 2017 2:36 pm Post subject: |
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Hi everyone
Some solutions are biunivocal.
R4C9 <>2 with R4C1 <>5
R5C2 <>3 with R5C7 <>2
R5C8 <>9 with R6C9 <>1
Ciao a Tutti
Paolo |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Fri Aug 25, 2017 4:47 pm Post subject: |
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I'll add one to Gianni's list:
W-Wing(25)b69, SL 2 in c7=> -5r5c8,r9c9 |
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Ajò Dimonios
Joined: 01 May 2017
Posts: 339
Location: Sassari Italy
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| Posted: Fri Aug 25, 2017 6:37 pm Post subject: |
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Hi Marty
Marty wrote:
| Quote: | | W-Wing(25)b69, SL 2 in c7=> -5r5c8,r9c9 |
Also R5C8 = 5 and R9C9 = 5 is in biunivoca with R4C9 = 2. This means that the AIC of my previous post and the W-Wing (25) b69, SL2 in c7 have the same logical basis.
Hello to all
Paolo |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Fri Aug 25, 2017 6:48 pm Post subject: |
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| What does biunivoca mean? |
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Ajò Dimonios
Joined: 01 May 2017
Posts: 339
Location: Sassari Italy
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| Posted: Fri Aug 25, 2017 7:26 pm Post subject: |
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Hi Marty
Biunivoca simply means that when R5C8 = 5 also R4C9 = 2 and when R4C9 = 2 also R5C8 = 5. When this happens if I prove the falsity of R5C8 = 5 I also demonstrated the falseness of R4C9 = 2 and vice versa
Ciao a Tutti
Paolo |
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