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immpy
Joined: 06 May 2017 Posts: 571
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Posted: Tue Nov 03, 2020 5:06 pm Post subject: VH 110320 |
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Hello all, enjoy the puzzle...
Code: |
+-------+-------+-------+
| . . 9 | 6 7 1 | 2 . . |
| 3 . . | . . . | . . 6 |
| . . . | . 2 . | . . . |
+-------+-------+-------+
| . 6 . | 9 . 8 | . 5 . |
| 5 . . | . . . | . . 1 |
| . 7 . | 5 . 3 | . 8 . |
+-------+-------+-------+
| . . . | . 8 . | . . . |
| 6 . . | . . . | . . 4 |
| . . 7 | 2 3 9 | 8 . 5 |
+-------+-------+-------+
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Play this puzzle online at the Daily Sudoku site
cheers...immp |
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storm_norm22
Joined: 24 Oct 2020 Posts: 15
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Posted: Tue Nov 03, 2020 10:58 pm Post subject: |
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shortest path
Quote: | is xy wing then xy wing?
(2=9)r7c1 - (9=7)r7c9 - (7=2)r4c9; r4c1 <> 1
then
(7=3)r4c7 - (3=9)r8c7 - (9=7)r7c9; r4c9 <> 7 |
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storm_norm22
Joined: 24 Oct 2020 Posts: 15
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Posted: Tue Nov 03, 2020 11:09 pm Post subject: |
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this doesn't solve it. If you are looking for a cool way to eliminate some candidates using some Unique rectangle logic then in the image below you can see that the 4's in the UR (46)r56c57 only have the escape cells of r4c57 within the columns of the UR. these 4's then are strongly inferenced and eliminate the 4's in r4c13
the same can be said of the 4's in r56c13
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TomC
Joined: 30 Oct 2020 Posts: 358 Location: Wales
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Posted: Wed Nov 04, 2020 8:48 am Post subject: |
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My solution W wing then W wing?
39 wing in r5c8 and r8c7 eliminates 3s in r45c7 (and r89c8)
This sets r5c8 to 3 and r4c3 to 3
Then 29 wing in r7c1 and r6c9 eliminates 9 from r7c9 = 7 |
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dongrave
Joined: 06 Mar 2014 Posts: 568
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Posted: Wed Nov 04, 2020 11:59 am Post subject: |
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Code: | +---------------+-------------+----------------+
| 8 5 9 | 6 7 1 | 2 4 3 |
| 3 2 14 | 8 9 45 | 157 17 6 |
| 7 14 6 | 3 2 45 | 159 19 8 |
+---------------+-------------+----------------+
| 124 6 1234 | 9 14 8 | 347 5 27 |
| 5 389 348 | 7 46 2 | 3469 39 1 |
| 1249 7 124 | 5 146 3 | 469 8 29 |
+---------------+-------------+----------------+
| 29 39 5 | 4 8 6 | 1379 12379 79 |
| 6 389 238 | 1 5 7 | 39 239 4 |
| 14 14 7 | 2 3 9 | 8 6 5 |
+---------------+-------------+----------------+
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7*r4c9-(7=9)r7c9-(9=2)r7c1-(2=1|4)r4c15-(47*=3)r4c7-(3=9)r8c7; contradiction (i.e. 9r7c9, 9r8c7) => r4c9 <> 7; stte. |
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immpy
Joined: 06 May 2017 Posts: 571
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Posted: Wed Nov 04, 2020 5:03 pm Post subject: |
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Nice to see all of the different approaches to solving. Thanks everyone.
cheers...immp |
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