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Dec 07 VH

 
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TomC



Joined: 30 Oct 2020
Posts: 358
Location: Wales
PostPosted: Tue Dec 07, 2021 9:51 am    Post subject: Dec 07 VH Reply with quote
Code:

+-------------+--------------+--------------+
| 3 5    89   | 689  169 4   | 7    189 2   |
| 6 28   2489 | 7    159 59  | 3    189 14  |
| 7 1    489  | 89   3   2   | 458  589 6   |
+-------------+--------------+--------------+
| 8 46   3    | 456  2   7   | 145  15  9   |
| 2 9    7    | 45   8   1   | 6    3   45  |
| 5 46   1    | 3469 469 369 | 2    7   8   |
+-------------+--------------+--------------+
| 4 38   58   | 2    7   359 | 1589 6   135 |
| 1 37   6    | 349  459 8   | 59   2   357 |
| 9 2378 258  | 1    56  356 | 58   4   357 |
+-------------+--------------+--------------+

Play this puzzle at the Daily Sudoku site

145 XY wing in box 3 and 6 gives -1 in r12c8
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ZeroAssoluto



Joined: 05 Feb 2017
Posts: 941
Location: Rimini, Italy
PostPosted: Tue Dec 07, 2021 2:53 pm    Post subject: Reply with quote
Hi everyone,

after
Locked Candidates with number 8 in r79c7 and -8 in r3c7
W-Wing 4,5 in r3c7,r5c9 SL with number 5 in r34c8 and -4 in r2c9.r4c7

Ciao Gianni
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TomC



Joined: 30 Oct 2020
Posts: 358
Location: Wales
PostPosted: Tue Dec 07, 2021 6:16 pm    Post subject: Reply with quote
Gianni, thanks for pointing out another basic move.

Code:

+-------------+--------------+--------------+
| 3 5    89   | 689  169 4   | 7    189 2   |
| 6 28   2489 | 7    159 59  | 3    189 14  |
| 7 1    489  | 89   3   2   | 45   589 6   |
+-------------+--------------+--------------+
| 8 46   3    | 456  2   7   | 145  15  9   |
| 2 9    7    | 45   8   1   | 6    3   45  |
| 5 46   1    | 3469 469 369 | 2    7   8   |
+-------------+--------------+--------------+
| 4 38   58   | 2    7   359 | 1589 6   135 |
| 1 37   6    | 349  459 8   | 59   2   357 |
| 9 2378 258  | 1    56  356 | 58   4   357 |
+-------------+--------------+--------------+

Play this puzzle at the Daily Sudoku site

So from this position, you could also have:

-5 in r789c7 as then r3c7=4, r4c7=1, r4c8=5 leads to no <5>'s in box 3
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Mogulmeister



Joined: 03 May 2007
Posts: 1151
PostPosted: Wed Dec 08, 2021 8:33 am    Post subject: Reply with quote
Putting a 5 in r789c7 makes r3c7 = 4 and r2c9 = 1 which puts another 5 in r789c9 <357>.

You can't have two 5's in box 9 so r789c7 can not be 5.
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