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Aug 12 VH

 
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ZeroAssoluto



Joined: 05 Feb 2017
Posts: 942
Location: Rimini, Italy
PostPosted: Fri Aug 12, 2022 9:37 am    Post subject: Aug 12 VH Reply with quote
Hi everyone,

Code:

+------------+--------+-----------+
| 3  8   27  | 5  9 1 | 47  24 6  |
| 5  4   279 | 37 8 6 | 79  23 1  |
| 69 679 1   | 37 2 4 | 8   5  39 |
+------------+--------+-----------+
| 2  79  79  | 6  5 8 | 3   1  4  |
| 4  5   6   | 1  7 3 | 2   9  8  |
| 8  1   3   | 9  4 2 | 5   6  7  |
+------------+--------+-----------+
| 69 2   5   | 8  1 7 | 469 34 39 |
| 1  69  8   | 4  3 5 | 69  7  2  |
| 7  3   4   | 2  6 9 | 1   8  5  |
+------------+--------+-----------+

Play this puzzle online at the Daily Sudoku site

Quote:
XY-Wing
3,7,9 in r2c47,r3c9 and -3 in r2c8,r3c4
3,7,9 in r2c7,r3c49 and -7 in r2c4
W-Wing 7,9 in r2c7,r4c3 SL with number 7 in r1c37 and -9 in r2c3


Ciao Gianni
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TomC



Joined: 30 Oct 2020
Posts: 358
Location: Wales
PostPosted: Fri Aug 12, 2022 11:56 am    Post subject: Reply with quote
X-wing on <9> in r37c19 removes <9> from r3c2 and r7c7

Then with only one cell containing 3 options it is a BUG pattern that shows that r2c3 cannot be <29> so must be <7> to solve
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TomC



Joined: 30 Oct 2020
Posts: 358
Location: Wales
PostPosted: Fri Aug 12, 2022 2:59 pm    Post subject: Another way Reply with quote
r1c3 = 2 to solve

Code:

+----------------+--------+--------------+
|  3    8   x27  | 5  9 1 | f47  e24  6  |
|  5    4    279 | 37 8 6 |  79  d23  1  |
| a69  b679  1   | 37 2 4 |  8    5  c39 |
+----------------+--------+--------------+
|  2    79   79  | 6  5 8 |  3    1   4  |
|  4    5    6   | 1  7 3 |  2    9   8  |
|  8    1    3   | 9  4 2 |  5    6   7  |
+----------------+--------+--------------+
|  69   2    5   | 8  1 7 |  469  34  39 |
|  1    69   8   | 4  3 5 |  69   7   2  |
|  7    3    4   | 2  6 9 |  1    8   5  |
+----------------+--------+--------------+

Either <ab> is a naked pair <69> or it isn't

If <ab> is a pair <69> then c=3, d=2, e=4, f=7 leads to x is NOT <7>
If <ab> is NOT a pair <69> then b=7 leads to x is NOT <7>

So either way, x is NOT <7>, so must be <2>
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