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ZeroAssoluto
Joined: 05 Feb 2017 Posts: 942 Location: Rimini, Italy
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Posted: Fri Nov 11, 2022 10:26 am Post subject: Nov 11 VH |
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Hi everyone,
Code: |
+-------------+---------------+-----------------+
| 4 15 9 | 6 8 17 | 257 3 25 |
| 17 6 378 | 2 5 137 | 478 478 9 |
| 2 35 3578 | 4 9 37 | 5678 1 56 |
+-------------+---------------+-----------------+
| 3 7 26 | 5 124 469 | 12469 469 8 |
| 8 49 1 | 7 24 469 | 3 4569 2456 |
| 5 49 26 | 139 1234 8 | 12469 469 7 |
+-------------+---------------+-----------------+
| 17 8 3457 | 139 6 2 | 4579 4579 345 |
| 6 135 357 | 1389 134 49 | 5789 2 35 |
| 9 2 34 | 38 7 5 | 468 468 1 |
+-------------+---------------+-----------------+
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Play this puzzle online at the Daily Sudoku site
Quote: | X-Wing with number 7 in r27c18 and -7 in r2c367,r7c37
AND
W-wing 3,8 in r2c3,r9c4 SL with number 8 in r29c8 and -3 in r9c3
AND
XY-Wing 1,3,7 in r2c16,r3c6 and -7 in r3c3
OR with only 1 step with some AIC
if r2c1=7 -7 in r23c3,r7c1
if r2c1=1 r1c6=1 r1c7=7 r8c3=7 and -7 in r23c3,r7c1
OR
if r2c3=3 -3 in r3c2,r789c3
if r2c3 is not 3 r2c6=3 r2c1=1 r7c1=7 r2c8=7 r1c6=7 r3c6=3 r8c2=3 and -3 in r3c2,r789c3 |
Ciao Gianni |
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TomC
Joined: 30 Oct 2020 Posts: 358 Location: Wales
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Posted: Fri Nov 11, 2022 1:29 pm Post subject: |
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Remove <1> from r2c1 to solve
Code: |
+-----------------+-----------------+---------------------+
| 4 m15 9 | 6 8 x17 | e257 3 f25 |
| a17 6 378 | 2 5 137 | 478 d478 9 |
| 2 35 3578 | 4 9 37 | 5678 1 56 |
+-----------------+-----------------+---------------------+
| 3 7 26 | 5 124 469 | 12469 469 8 |
| 8 49 1 | 7 24 469 | 3 4569 2456 |
| 5 49 26 | 139 1234 8 | 12469 469 7 |
+-----------------+-----------------+---------------------+
| b17 8 3457 | 139 6 2 | 4579 c4579 345 |
| 6 135 357 | 1389 134 49 | 5789 2 35 |
| 9 2 34 | 38 7 5 | 468 468 1 |
+-----------------+-----------------+---------------------+
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The X-wing on <7> in abcd and the <1>'s in mx produce the contradiction:
If a=1 then d=7, e<>7, x=7
If a=1 then m<>1, x=1 |
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TomC
Joined: 30 Oct 2020 Posts: 358 Location: Wales
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Posted: Fri Nov 11, 2022 3:02 pm Post subject: |
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Another way to look at this is an Almost Naked Pair in r1c79 (ef)
If r1c79 is a <25> pair then m=1, a=7
If r1c79 is NOT a <25> pair then e=7, d<>7, c=7, b<>7, a=7 |
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